[texhax] \doublehyphendemerits

Morten Høgholm morten.hoegholm at gmail.com
Thu May 3 11:28:56 CEST 2007


On 5/2/07, Philip Taylor (Webmaster) <P.Taylor at rhul.ac.uk> wrote:
> As it's a demerit, it's in units of badness squared,
> so I suspect >= 10 000 ^ 2.

Yup, that's right. One surefire way to do it is to set to the largest
maximum number in TeX, namely 2^{31} - 1 = 2147483647.
-- 
Morten


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